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4.9x^2+8x-350=0
a = 4.9; b = 8; c = -350;
Δ = b2-4ac
Δ = 82-4·4.9·(-350)
Δ = 6924
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{6924}=\sqrt{4*1731}=\sqrt{4}*\sqrt{1731}=2\sqrt{1731}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-2\sqrt{1731}}{2*4.9}=\frac{-8-2\sqrt{1731}}{9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+2\sqrt{1731}}{2*4.9}=\frac{-8+2\sqrt{1731}}{9.8} $
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